A thin spherical shell of mass M = 2.00 kg is released from rest at the top of a

Question

A thin spherical shell of mass M = 2.00 kg is released from rest at the top of an incline of height H=1.47 m and rolls without slipping to the bottom. The ramp is at an angle of ? = 28.9o to the horizontal. Calculate the speed of the sphere's CM at the bottom of the ramp.

A thin spherical shell of mass M = 2.00 kg is released from rest at the top of an incline of height H=1.47 m and rolls without slipping to the bottom. The ramp is at an angle of ? = 28.9o to the horizontal. Calculate the speed of the sphere's CM at the bottom of the ramp.

Explanation / Answer

mgh=0.5mv^2+0.5(0.4)mr^2w here no slipping implies v=rw replacing w with v/r we get mgh=0.7mv^2 V=4.537m/s hence the ans speed of Cm =4.537 m/s cheers :)

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