3. Assign the correct term: (2.0 pts.) aa = Aa a 4. Name all 5 assum Mardy-Weinb
ID: 190754 • Letter: 3
Question
3. Assign the correct term: (2.0 pts.) aa = Aa a 4. Name all 5 assum Mardy-Weinberg Equilibrium Theory: (2.0 pts.) 1) 4) 5) Calculate the Allele frequency for the following data: (4.0 pts) (Need to show ALL DD = 100 Dd-300 dd = 50 Population total- Allele Frequency: Dd 5. Calculate the observed genotype frequencies below: Observed values: DD Dd = dd = Now, calculate the expected values for the above alleles: Expected values: DD= Dd = onus (1pts) - Briefly explain the difference(s) between Natural Selection andExplanation / Answer
Population Total = Number of DD + Dd + dd individuals = 100+300+50=450
Allele frequency of D = (Number of DD individuals + (1/2)*Number of Dd individuals)/Population Total = (100 + 300/2)/450 = 250/450 = 0.55
Allele frequency of d = (Number of dd individuals + (1/2)*Number of Dd individuals)/Population Total = (50 + 300/2)/450 = 200/450 = 0.44
Observed genotype frequency of DD = Number of DD individuals / Population Total = 100/450 = 0.22
Observed genotype frequency of Dd = Number of Dd individuals / Population Total = 300/450 = 0.66
Observed genotype frequency of dd = Number of dd individuals / Population Total = 50/450 = 0.11
As per Hardy-Weinberg Principle:
Expected genotype frequency of DD = (Allele frequency of D)^2 = 0.55^2 = 0.309
Expected genotype frequency of Dd = 2*Allele frequency of D*Allele frequency of d = 2*0.55*0.44 = 0.494
Expected genotype frequency of dd = (Allele frequency of d)^2 = 0.44^2 = 0.198
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