A rock is thrown from the top of a 30.0 meter high cliff at an angle of 25.0 deg

Question

A rock is thrown from the top of a 30.0 meter high cliff at an angle of 25.0 degrees above the horizontal and a speed of 15.0 m/s. How much does it take for the rock to reach it's maximum height above the ground? 0.65s Which of the quantities listed below do not change during the rock's flight? The horizontal component of the velocity of the rock and the vertical component of the acceleration of the rock Need help understanding!

Explanation / Answer

We generally do not answer the questions of those who are having low rating. You are having a rating of "65%". Please rate all answers and improve your rating. Even if you find the answers are incorrect, rate them as not helpful. But do rate them for the good of both of us. Thanks!! Coming to the problem Vertical velocity = (15*sin(radians(25))) m/s = u Final vertical velocity at maximum height = v = 0 acceleration = a = -g = -9.81 m/s^2 v = u+at =>t = u/a = (15*sin(radians(25)))/9.81 = 0.65 seconds The horizontal component of the velocity of the rock do not change during the rock's flight because there is no acceleration or deceleration in horizontal direction.

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