Water is flowing in a pipe with a varying cross-sectional area, and at all point

Question

Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is .070m^2, and the magnitude of the fluid velocity is 3.5m/s^2 . Part A What is the fluid speed at point in the pipe where the cross-sectional area is .105m^2?(Express all answers to 4 sig figs). Part B What is the fluid speed at point in the pipe where the cross-sectional area is .047m/s? Part C Calculate the volume of water discharged from the open end of the pipe in 1.00hr. Will give 5 stars to the person who answers with the most detailed explanation. Include all formulas and steps pleaz. Thanks.

Explanation / Answer

F = v1*A1 = v2*A2 v2 = v1*(A1/A2) We know that v1 = 3.5 m/s and A1 = 7*10^-2 m^2, so at the point where the pipe has a cross-sectional area of 0.102 m^2, the speed is: v2 = (3.5 m/s)*(7.00*10^-2)/(0.105) = 2.33 m/s At the point where the pipe has a cross-sectional area of 4.70*10^-2 m^2, the speed is: v2 = (3.5 m/s)*(7.00*10^-2)/(4.70*10^-2) = 5.21 m/s

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