The four wires in the figure are tilted at 20 with respect to a uniform 0.35 fie
ID: 1908470 • Letter: T
Question
The four wires in the figure are tilted at 20 with respect to a uniform 0.35 field. Each carries 4.5 and is 0.35 long.
A.What is the magnitude of the force on the wire a?
B.What is the direction of the force on the wire a?
C.What is the magnitude of the force on the wire b?
D.What is the direction of the force on the wire b?
E.What is the magnitude of the force on the wire c?
F.What is the direction of the force on the wire c?
G.What is the magnitude of the force on the wire d?
H.What is the direction of the force on the wire d?
a B b d cExplanation / Answer
Force = IL X B
= BILSin
is the Angle between I and B
For Wire a
F = 0.35*0.35*4.5*Sin(20)
= 0.1885 N
Direction is Into the Paper i.e, Away from Observer
===============================================
For Wire b
F = 0.35*0.35*4.5*Sin(180-20)
= 0.1885 N
Direction is Into the Paper i.e, Away from Observer
=============================================
For Wire c
F = 0.35*0.35*4.5*Sin(180-20)
= 0.1885 N
Direction is out of the paper, i.e, Towards Observer
===============================================
For Wire d
F = 0.35*0.35*4.5*Sin(20)
= 0.1885 N
Direction is out of the paper, i.e, Towards Observer
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