9. [2pt] A pipe, of length L = 0.362 m and diameter d = 0.089 m is open at both

Question

9. [2pt] A pipe, of length L = 0.362 m and diameter d = 0.089 m is open at both ends. A loudspeaker is placed near one end and its frequency is varied. What is the second-lowest frequency for which the sound in the pipe resonates? Assume 343 m/s as the speed of sound in air. (Use the information and figures in section 16.4 of your textbook for help.) Answer: 10. [2pt] The air in another pipe, of the same dimensions but with one end closed, is excited by the loudspeaker. What is the second-lowest frequency for which this occurs?

Explanation / Answer

Open) f = nv/2(L+0.3d) n = 2 for first case substitute the values and solve. Closed) f = nv/4(L+0.4d) n = 2 again for this case substitute and get results.

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