A bumper car with mass m1 = 119.0 kg is moving to the right with a velocity of v

Question

A bumper car with mass m1 = 119.0 kg is moving to the right with a velocity of v1 = 4.4 m/s. A second bumper car with mass m2 = 83.0 kg is moving to the left with a velocity of v2 = -3.5 m/s. The two cars have an elastic collision. Assume the surface is frictionless.

A)the velocity of the center of mass of the system? 1.154 m/s

B) the initial velocity of car 1 in the center-of-mass reference frame? 3.246 m/s

C)What is the final velocity of car 1 in the center-of-mass reference frame? -3.246 m/s

D)What is the final velocity of car 1 in the ground (original) reference frame? -2.092m/s

5) What is the final velocity of car 2 in the ground (original) reference frame? m/s

6) In a new (inelastic) collision, the same two bumper cars with the same initial velocities now latch together as they collide. What is the final speed of the two bumper cars after the collision? m/s

7) Compare the loss in energy in the two collisions:

|?KEelastic| = |?KEinelastic|

|?KEelastic| > |?KEinelastic|

|?KEelastic| < |?KEinelastic|

Explanation / Answer

5) as solved in ur last question, v2' = 5.807 m/s i.e 5.807 m/s towards right

6)since the collision is inelastic, external forces are zero, therefore Vcom will not change,
final speed v=vcom = 1.1514 m/s towards right

7)due to inelastic collision, there will be some loss of energy,

therefore, KE inelastic < KE elastic i.e 2nd option..

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