The mass m = 13 kg shown in the figure is displaced a distance x to the right fr

Question

The mass m = 13 kg shown in the figure is displaced a distance x to the right from its equilibrium position. (Take k1 = 108 N/m and k2 = 196 N/m.) (a) What is the net force acting on the mass? (Use any variable or symbol stated above along with the following as necessary: k_eff for the effective spring constant.) Fnet = What is the effective spring constant? (b) What will the frequency of the oscillation be when the mass is released? f = (c) If x = 0.1 m, what is the total energy of the mass-spring system after the mass is released, and what is the maximum velocity of the mass? Etotal = vmax =

Explanation / Answer

if it is displaced in either of the direction both springs are in opposing the displacement so net force due to springs will add f= k1x +k2x =(k1+k2)x a) effective spring constant = k eff =k1+k2 =304 b)w=(keff/m)^0.5 =4.83 c)total energy =0.5 keff *amplitude^ 2 = 0.5 *304 *0.1*0.1=1.52 j

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