A 0.500 kg sphere moving with a velocity (2.00 - 3.40 + 1.00) m/s strikes anothe

Question

A 0.500 kg sphere moving with a velocity (2.00 - 3.40 + 1.00) m/s strikes another sphere of mass 1.50 kg moving with a velocity (-1.00 + 2.00 - 3.60) m/s. (a) If the velocity of the 0.500 kg sphere after the collision is (-0.90 + 3.00 - 8.00) m/s, find the velocity of the 1.50 kg sphere and identify the kind of collision (elastic, inelastic, or perfectly inelastic). b) b) If the velocity of the 0.500 kg sphere after the collision is (-0.250 + 0.650 - 2.45) m/s, find the final velocity of the 1.50 kg sphere and identify the kind of collision. ( + + ) m/s c) What if? If the velocity of the 0.500 kg sphere after the collision is (-1.00 + 2.60 + a) m/s, find the value of a and the velocity of the 1.50 kg sphere after an elastic collision. (Two values of a are possible, a negative value and a positive value. Report each with their corresponding final velocities.) a (positive value) m/s2 v2f = m/s a (negative value) m/s2 v2f = m/s

Explanation / Answer

momentum conservation (a) 0.5(2.00i - 3.40j + 1.00k) + 1.50(-1.00i + 2.00j - 3.60k) = 0.500(-0.90i + 3.00j - 8.00k) + 1.5V hence 1.5V = -0.05i + 1.5j -0.9k or V = -0.033i + j - 0.6k collision is inelastic since spheres are neither stuck nor at rest after collision. use the same formula for all other parts

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