A 1.2-kg mass suspended from a spring of spring constant 22 N.m-1 executes simpl
ID: 1913739 • Letter: A
Question
A 1.2-kg mass suspended from a spring of spring constant 22 N.m-1 executes simple harmonic motion of amplitude 5 cm. What is the period T and frequency f of this oscillation? A mass of 1.2 kg attached to a spring is in simple harmonic motion along the x-axis with a period T = 2.5 s. If the total energy of the system is 2.7 J, what is the amplitude of the oscillation? An 8.0-kg block is attached to a spring with a spring constant of . If the spring is stretched 3.0 cm from its equilibrium position and released from rest, the maxium velocity attained by the mass is? Enter question here...Explanation / Answer
time period = 2*pi*(m/k)^0.5 = 1.467 sec frequency = 1/T = 0.681 Hz b) T = 2*pi*sqrt(m/k) = 2.5 => k = 7.57 N/m at extreme points 0.5*k*A^2 = 2.7 => A = 0.84 m c) value of spring constant is missing in question if known 0.5*k*A^2 = 0.5*m*v^2 we can get V
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