3. Mutation-Selection Balance. Use the PopG program and obtain the expected alle

Question

3. Mutation-Selection Balance. Use the PopG program and obtain the expected allele frequency of a deleterious mutation 'a' at equilibrium (q) The relative fitness for 'AA' = 1' for 'Aa-0.80 and for 'aa,-0.60. Mutation rate from ' to 'a' is 0.05. Use initial frequency of 'A'-0.5 and a Population Size (N) 1000. The Blue line will show expectations with no Drift for allele 'A'. a) What is the frequency of this deleterious allele 'a' (q) at equilibrium (blue line)? b) Is this what you expected based on theory? Explain.

Explanation / Answer

(a)

0.60 aa individuals contain=0.36 a genes

0.80 A a individuals contain=0.80 a genes

Total 1000 individuals          =2000 genes

                                                =1.16/2000 =0.00058%

Here frequency of deleterious

                                  Alleles a}q=0.00058%

(b) Mutation rate from A to a is 0.05.this is very less when compare to the initial frequency of A=0.5

                        A----------a    =0.05(final)

                        A----------a    = 0.5(initial)

Nature select a dominant individuals so dominant mutation was occur. Thereby (aa) frequency is very less=0.00058% (aa).

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