A small positively charged ball, A of mass m is suspended by a thread of negligi

Question

A small positively charged ball, A of mass m is suspended by a thread of negligible mass. Another identical positively charged ball, B is moved very slowly from a large distance until it is in the origin position of ball A. As a result, ball A rises vertically by h. How mu Ch work has been done? Express your answer in term of mgh. How will the answers change if the length of thread increase by 2 times? the incoming ball B carries 8 times as mu Ch charge?

Explanation / Answer

a)let in the final position of the ball A the angle made by the thread be Q and the total length of the thread in the original position be L thus work done = mg(L-LcosQ) b) i) the workdone would be twice ii)only the angle would change to a greater value say @ i.e. (@>Q) please rate me first for my complete answer

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