A point charge q2 = -3.2 ?C is fixed at the origin of a co-ordinate system as sh

Question

A point charge q2 = -3.2 ?C is fixed at the origin of a co-ordinate system as shown. Another point charge q1 = -0.4 ?C is is initially located at point P, a distance d1 = 9.4 cm from the origin along the x-axis.What is ?PE, the change in potenial energy of charge q1 when it is moved from point P to point R, located a distance d2 = 3.8 cm from the origin along the x-axis as shown?The charge q2 is now replaced by two charges q3 and q4 which each have a magnitude of -1.6 ?C, half of that of q2. The charges are located a distance a = 2.3 cm from the origin along the y-axis as shown. What is ?PE, the change in potential energy now if charge q1 is moved from point P to point R?What is the potential energy of the system composed of the three charges q1, q3, and q4, when q1 is at point R? Define the potential energy to be zero at infinity.

Explanation / Answer

first we have to start with what equation we know. To find the potential energy between two points we use the equation U = (kQq)/r. At the first point we have U1 = (k(1e-6)(5e-6))/(.077) At the second point we have U2 = (k(1e-6)(5e-6))/(.031) To find the change in U, we do ?U = U2 - U1. Just remember that the units Q and q should be in Coulombs and r should be meters.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.