A hollow metal sphere has 7 and 11 inner and outer radii, respectively. The surf

Question

A hollow metal sphere has 7 and 11 inner and outer radii, respectively. The surface charge density on the inside surface is . The surface charge density on the exterior surface is -150nC/m^2. The surface charge density on the exterior surface is +150nC/m^2. A. What is the strength of the electric field at point 4 cm from the center? B. What is the direction of the electric field at point 4 cm from the center? C. What is the strength of the electric field at point 8 cm from the center? D. What is the direction of the electric field at point 8 cm from the center? E.What is the strength of the electric field at point 12 cm from the center? F.What is the direction of the electric field at point 12 cm from the center?

Explanation / Answer

2. Relevant equations Inner Surface Charge = n = Q/A E = K*q/r^2 3. The attempt at a solution Well I got the 1st one right: Convert all the nC and cm to C and M. E (at .04 m) = = [K * q]/r^2 = [K * nA]/r^2 = [K * n(4(pi)R^2)]/r^2 (note R = inner sphere radius and r = 4 cm from center) For the 2nd part I'm unsure. How do I found out the charge on the part of the sphere in between the hollow and exterior at 8 cm? Is it q = nA - nA_2? q = [1*10^-17 * 4pi(.1m)^2] - [-1*10^-17 * 4pi(.6m)^2]

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