A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerat

Question

A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was cross Map with another homozygous variety with normal leaves. All the F1 had lacerate leaves (jagged-edged leaves Two Fi plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy? O O O two genes, where one allele at a single locus is recessive lethal two genes. with a dominant allele at both looci two genes, with a dominant allele at either or both loci one gene, with codominant alleles at a single locus Continued below... Give genotypes for all the plants in the P. Fs, and F2 generations. Some generations will have more than one genotype F1 Fz (lacerate) F2 (normal) O Previous Give Up & View Salution 0 Check Answer-Next Exi ? Hint

Explanation / Answer

There are two genes, with a dominant allele at each loci, because of which the standard 9:3:3:1 ratio became a 15:1 ratio.

P - AABB, aabb

F1 - AaBb

F2 (lacerate): AABB, AABb, AAbb, AaBB AaBb, Aabb, aaBB, aaBb

F2 (normal): aabb

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