please answer it Express atmospheric pressure in meter of water column and in cm

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please answer it

Express atmospheric pressure in meter of water column and in cm of mercury column. Determine the intensity of pressure in water at a depth of 5m. below the free surface of water. Specific gravity of sea water is 1.01. Determine the intensity of pressure in Pa and force in kN on a horizontal lamina held at a depth of 1 km from the free surface of seawater The surface area of the lamina is 3m x 2m. Convert intensity; of pressure of 2MPa into equivalent pressure head of oil of specific gravity 0.8. The specific gravity of oil is 0.75. Determine the depth of a point within the oil at which the intensity' of pressure is 0.1 N/mm2 What are the gauge pressure and absolute pressure at a point 3m below the free surface oi a liquid having a density of 1500 kg/m3 if the atmospheric pressure is equivalent to 75mm of mercury ? Density of water is 1000 kg /m3 The fallowing figure (fig 1) shows a pipe line containing water. Determine the pressure head at I in meter of water. Also determine t

Explanation / Answer

1.

Atmospheric pressure = 101325 Pa

Water density = 1000 kg/m^3

P = rho*g*h

101325 = 1000*9.81*h

h = 10.329 m

Mercury density = 13588 kg/m^3

101325 = 13588*9.81*h

h = 0.76012 m = 76.012 cm

2.

P = rho*g*h

Water density rho = 1000 kg/m^3

P = 1000*9.81*5

P = 49050 Pa

3.

Density of seawater rho = S.G*density of water

= 1.01*1000

= 1010 kg/m^3

P = rho*g*h

P = 1010*9.81*(1*10^3)

P = 9908100 Pa = 9908.1 kPa

Force = Pressure*area

= 9908.1*(3*2)

= 59448.6 kN

4.

Pressure = 2 MPa = 2*10^6 Pa

Density of oil = 0.8*1000 = 800 kg/m^3

P = rho*g*h

2*10^6 = 800*9.81*h

h = 254.84m

5.

P = 0.1 N/mm^2 = 0.1*10^6 N/m^2

Oil density, rho = 0.75*1000 = 750 kg/m^3

P = rho*g*h

0.1*10^6 = 750*9.81*h

h = 13.5915 m

6.

Atmospheric pressure = 750 mm of mercury = 0.75 m

Density of mercury = 13588 kg/m^3

P = rho*g*h

P_atm = 13588*9.81*0.75

P_atm = 99973.7 Pa

Gage pressure of point = rho_fluid*g*h

= 1500*9.81*3

= 44145 Pa

Absolute pressure = P_amb + P_gage

= 99973.7 + 44145

= 144118.7 Pa

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