A complete mix activated sludge plant operates at design Q, with the reactor tan

Question

A complete mix activated sludge plant operates at design Q, with the reactor tank volume set by a nominal residence time of 6 hours..

a) It was anticipated that it would operate at 25% RAS for an expected Xr= 2,000 mg/l. What would the actual residence time be?

b) The secondary clarifier only produces Xr= 1,000 mg/l, so RAS is increased to 50% Q. What is the actual residence time then? Does the F/M, the MLVSS concentration and SRT change?

c) The secondary clarifier actually produces 3,000 mg/l Xr, but RAS stays at 25% as originally planned. Do F/M, MLVSS and SRT change from what was planned??

Explanation / Answer

Residence time=24*(V/Q)

RAS%= Qr/Q (100)

Qr = (QX)/(Xr-X)

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