It should be simple at least. I need to know how ~C+BC = (~C + B) Please show al
ID: 1922707 • Letter: I
Question
It should be simple at least. I need to know how ~C+BC = (~C + B)Please show all the work and what properties you used. I've been trying to show how it is by using the identities but I can't seem to find out how. Please help. I'm trying to solve some boolean algebra questions but whenever i run into something with this form i get stuck. Yes i know that the two equations do equal each other, but that's not the point. Its bothering me that i don't know HOW it equals each other, and i hate to just memorize something that i should be understanding.
Thanks guys....
By the way ~C means NOT C.
Explanation / Answer
~C+BC = (~C + B)
= (~C+C) (~C+B)
= 1*(~C+B)
= (~C+B)
as u wanted
used property.
a +(bc) = (a + b)(a + c) a(b + c) = ab + ac Distributivity
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