The active region is defined by the biasing arrangements of Fig. 3.6. At the low

Question

The active region is defined by the biasing arrangements of Fig. 3.6. At the lower end of the active region the emitter current(IE) is zero, and the collector current is simply that due to the reverse saturation current Ieo, as induced in Fig. 3.9. The current Ico is so small(mi- Using the characteristics of Fig. 3.8, determine the resulting collector current if IE = 4mA and VCB = 4V. Repeat part(a) for IE = 4mA and VCB = 16 V. How have the changes in VCB affected the resulting level of Ic? On an approximate basis, how are IE and IC related based on the results above?

Explanation / Answer

the value of Ic is slightly less than I e..... this is because I e=I c+ I b.....where the value of I c >>I b.... so the value of I c doesn't varies much with the change in V cb.... A)I c= approximately equals to 4mA B)I c= approximately equals to 4mA

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