The 200F capacitor of the defibrillator circuit shown below is charged to 2 k V.
ID: 1930152 • Letter: T
Question
The 200F capacitor of the defibrillator circuit shown below is charged to 2 k V. When the electrodes are attached to the patient, a 50ohm resistive load is seen.
A)Calculate the peak current passing through the patient during the discharge under these condititions
B)Calculate the time constant of the discharge.
The 200½F capacitor of the defibrillator circuit shown below is charged to 2 k V. When the electrodes are attached to the patient, a 50ohm resistive load is seen. A)Calculate the peak current passing through the patient during the discharge under these condititions B)Calculate the time constant of the discharge.Explanation / Answer
a) peak current = 2kV/50ohm = 40 A b) time constant = RC = 50*200*10^-6 = 0.01 seconds
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