The figure shows an oscilloscope screen capture of a periodic signal. The oscill

Question

The figure shows an oscilloscope screen capture of a periodic signal. The oscilloscope settings are: time scale = 20 ms/div and voltage scale = 10 mV/div. What are the frequency and the maximum voltage for the signal shown? The minimum value of the signal is 0V.

The figure shows an oscilloscope screen capture of a triangular wave periodic signal. The oscilloscope settings are: horizontal time scale = 20 ns/div and vertical voltage scale = 10 mV/div. One cycle of the triangular wave covers 5 division in the horizontal axis and 2 divisions in the positive vertical axis and 2 divisions in the negative vertical axis.

Explanation / Answer

we see that 1 cycle of captured signal covers 5 horizontal divisions
=> T = 5 x (time scale) = 5 x 20 ms = 100 ms
=> f = 1/T = 10 Hz

we see that the max value is 4 division above the min value which is zero
=> V(max) = 4 x (Voltage scale) = 4 x 10 mV = 40 mV

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