A lead bullet weighing 0.0200 lbf and traveling horizontally at 3000 ft/s is sud

Question

A lead bullet weighing 0.0200 lbf and traveling horizontally at 3000 ft/s is suddenly stopped by a perfectly rigid object that does not deform during the impact. Find the temperature rise of the bullet assuming the impact occurs so rapidly that the impact process can be considered to be adiabatic. For lead, use delta u = 0.0130 (delta T) in Btu/lbm, where T is in °F or R.

As much explanation on the reasoning behind the steps taken to solve the problem, including units, as possible would be appreciated so I can better learn how to solve problems like this on my own. Thanks for any help.

Explanation / Answer

This is a simple problem of conservation of energy

The kinetic energy of the bullet while travelling gets transformed into the internal energy after striking(as the process is adiabtic)

So the equation goes like this

1/2mv2 = 0.0130 (delta T)

1/2 *0.02 *30002 = 0.0130 (delta T) *1000/0.02

delta T=138.46 F

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