Object O1 is 14.5 cm to the left of a converging lens with a 10.4-cm focal lengt

Question

Object O1 is 14.5 cm to the left of a converging lens with a 10.4-cm focal length. A second lens is positioned 10.0 cm to the right of the first lens and is observed to form a final image at the position of the original object, O1.
(a) What is the focal length of the second lens?
cm

(b) What is the overall magnification of this system?


(c) What is the nature (i.e., real or virtual, upright or inverted) of the final image?
virtual and upright
real and inverted
real and upright
virtual and inverted

Explanation / Answer

(a). analyzing for the first lens, 1/s + 1/s' = 1/f 1/15 + 1/s' = 1/10 s' = 30 cm analyzing for the second one, s = d - s' s = 10 - 30 s = -20 cm 1/s + 1/s' = 1/f 1/(-20) + 1/(-15 - 10) = 1/f f = -100/9 cm it's diverging lens. (b). M = (s'/s)(s'/s) M = (30/15)(-25/-20) M = 2.5 times

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