One thing to keep in mind is that the sun shines only on one half of the globe,

Question

One thing to keep in mind is that the sun shines only on one half of the globe, but the emission comes from all over the globe. Also, the 150 Wm^-2 from the atosphere will be all over the globe as well. This may help to get the 'right' result.

a) Determine the global average power density that the Earth's surface receives (ie., the total amount of sunlight falling on the Earth's surface), and then calculate the amount absorbed by taking into account the Earth's albedo.

I have b), c) and d) to ask. Check them out.

Explanation / Answer

1370 Wm2(1-0.3) = 959 Wm2/2 = 479.5 Wm2

You have to divide by two since the Sun is shining on only half of the world at one time

The emissivity or reflectivity of the Earth is 0.6 so therefore 0.4 of the above answer is absorbed by the Earth.

(0.4)(479.5 Wm2) = 191.8 Wm2

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.