A parachutist with a camera descends in free fall at a speed of 15 m/s. The para

Question

A parachutist with a camera descends in free fall at a speed of 15 m/s. The parachutist releases the camera at an altitude of 70 m.

(a) How long does it take the camera to reach the ground?
1.55 seconds
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Your response differs from the correct answer by more than 10%. Double check your calculations.




(b) What is the velocity of the camera just before it hits the ground?
30.282 m/s^2
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Your response differs from the correct answer by more than 10%. Double check your calculations. m/s

Explanation / Answer

Using standard kinematicequations:

     Z  =  Z0 +V0*t + (1/2)*a*t2

Camera hits ground at time "t" when
{Z = 0}, so we solve for "t" in  the
following:

     0  =  (70) + (-15)*t + (1/2)*(-9.81)*t2 

      t  = 2.546 sec

                 {Velocity @ Z =0}  = 
                     =  V0 +a*t
                     =  (-15) +(-9.81)*(2.546)
                     =  -39.976 m/sec

{TimeFor Camera To Reach Ground}  = 
                =  2.546  sec
    
 {Velocity Of Camera HittingGround}  = 
                = -39.98  m/sec

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