The brakes are applied to a car traveling on a dry, level highway. A typical val

Question

The brakes are applied to a car traveling on a dry, level highway. A typical value for the magnitude of the car's acceleration is 4.80 m/s2. If the car's initial speed is 27.0 m/s, how long does it take to stop and how far does it travel, starting from the moment the brakes are applied?

I found that the time to stop = 5.63 s
I just can't figure out the stopping distance. I have tried by using the formula:
X=Vi*t + (1/2)*at^2 and got 228.1 but it is saying that is incorrect.

I would really appreciate the help! :)

Explanation / Answer

You need to remember that the car is decelerating so it is -1/2 at^2 D= Vo -1/2 at^2 D= 27.0* 5.63 -1/2 *4.80 *(5.63)^2 D=75.937 m

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