A major leaguer hits a baseball so that it leaves the bat at a speed of 32.0 {\

Question

A major leaguer hits a baseball so that it leaves the bat at a speed of 32.0 { m m/s} and at an angle of 36.9^circ above the horizontal. You can ignore air resistance.

Part A
At what two times is the baseball at a height of 9.00 { m m} above the point at which it left the bat?
Enter your answer as two numbers, separated by a comma, in the order t_1, t_2, where t_2>t_1.
t_{1,2} =_____{ m s}


Part B
Calculate the horizontal component of the baseball's velocity at each of the two times you found in part A.
Enter your answer as two numbers, separated by a comma, in the order v_1, v_2.
v_{h:1,2} =_____ { m m/s}

Part C
Calculate the vertical component of the baseball's velocity at each of the two times you found in part A.
Enter your answer as two numbers, separated by a comma, in the order v_1, v_2.
v_{v:1,2} =_____{ m m/s}

Part D
What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat?
v =______ { m m/s}

Part E
What is the direction of the baseball's velocity when it returns to the level at which it left the bat?
heta = _______^circ below the horizontal

Explanation / Answer

Vo=32 m/s==>=36.9o==>voy=Vo*sin(36.9o)19.21 m/s

max ht t=voy/g=1.9606 s==>9=voy*t-1/2*9.8*t2=t=0.5439 s

vox=Vo*cos(36.9o)25.59 m/s==>1.9606+0.5439=2.5045s

Vy=voy-g*t==>19.21-9.8*0.543913.88 m/s

A) t_1 0.5439 s,t_2 2.5045 s

B) v_1 25.59 m/s,v_2 25.59 m/s

C) v_1 13.88 m/s,v_2 13.88 m/s

D) Vfinal=(vox2+vy2)=32 m/s

E) -36.9o

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