At amusement parks, there is a popular ride where the floor of a rotating cylind

Question

At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders "plastered" against the wall. Suppose the radius of the room is 3.25 m and the speed of the wall is 12.2 m/s when the floor falls away.

What is the source of the centripetal force acting on the riders?
A the gravitational force
B the normal force exerted on the rider by the wall
C the cavitron force between the rider and the wall
D the strong force between the rider and the wall
How much centripetal force acts on a 55.0 kg rider?
______________N
What is the minimum coefficient of static friction that must exist between the rider's back and the wall, if the rider is to remain in place when the floor drops away?
_______________________

Explanation / Answer

a) normal force exerted on the rider by the wall b) Given     mass of rider   m = 55 kg     Radius of room   r = 3.5 m     speed of wall v = 11.8 m/s     centripetal force acts on the rider                      F = m v 2 / r                          = ( 55 ) ( 11.8 ) 2 / 3.5 m                          = 2188 N c) F = mg      coefficient of static friction               = F / mg                    = 2188 / 55 *9.8                     = 4.05                                     

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