<p>Daniel takes his two dogs, Pauli the Pointer and Newton the Newfoundland, out

Question

<p>Daniel takes his two dogs, Pauli the Pointer and Newton the Newfoundland, out to a field and lets them loose to exercise. Both dogs sprint away in different directions, while Daniel stands still. From Daniel's point of view, Newton runs due North at 3.90 m/s, but Pauli's point of view, Newton appears to be moving at 1.30 m/s due East. What must Pauli's velocity relative to Daniel be for this to be true? Express your answer i unit vector notation if North is the +y-direction and East is the +x-direction, and then express your answer as a magnitude and an angle measured counter-clockwise from due East.</p>
<p>I have no clue where to even start with this problem. &#160;An answer and explanation would be greatly appreciated!</p>

Explanation / Answer

Vpd = Vpn+Vnd=-2.1i +4.4j

a) x comp = -1.3

b) y comp = 3.9

c) magnitude = sqrt(1.3^2+3.9^2) = 4.11 m/s

d) direction = tan ^-1(-1.3/3.9)=-18.43 = 90+18.43 = 108.43 degrees countr=er clock wise with east

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