In a tug of war, two teams pull on opposite ends of a rope, attempting to pull t

Question

In a tug of war, two teams pull on opposite ends of a rope, attempting to pull the other team across a dividing line. Team A accelerates toward team B at the rate of 0.109 m/s^2. Find all the horizontal forces acting on each team if the weight of each team is 1.06*10^4 N and the tension in the rope is 4.80*10^3 N.

Force of rope tension on team A: Answer given is 4800 N
Force of ground on team A: Answer given is 4680 N

Force of ground on team B: Answer given is 4920 N
Force of rope tension on B: Answer given is 4800 N

HOW DO YOU FIND THESE ANSWERS. SHOW STEPS PLEASE SO I CAN UNDERSTAND

Explanation / Answer

by newtons 3rd law rope tension on both teams=4800 N

Wa/g=1.06*104*0.109/9.8=117.89 N

let force of ground be F.

for A,

F=T-Wa/g=4800-117.89=4682.11 N

for B,

F=T+Wa/g=4800+117.89=4917.89 N

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