Question 1 A golfer takes two putts to get his ball into the hole once he is on

Question

Question 1

A golfer takes two putts to get his ball into the
hole once he is on the green. The first putt
displaces the ball 4 m east, and the second
5.96 m south.
What displacement would have been
needed to get the ball into the hole on the
first putt?
Answer in units of m

part 2

What is the direction (in degrees S of E)?
Answer in units of

Question 2

A stone is thrown from ground level at 71 m/s.
Its speed when it reaches its highest point is
53 m/s.
Find the angle, above the horizontal, of the stone’s initial velocity.
Answer in units of

Explanation / Answer

The coordinates for the first put are (4,0)m and the second are (0, -5.96)
To find the resultant

42  + 5.962 =  7.18m and the degrees would have been:

tan^-1 (5.96/4) = 56.13 degrees south of east

Part 2               
At the top, the stone only has a horizontal velocity so that is 53m/s. From that, you can get the vertical velocity by using the resultant velocity from which it was launched.

712 - 532 =47.24m/s

and angle is cos-1 (53/71) = 41.7 degrees

Hope that helps

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