A 6 kg block rests on a horizontal table, attached to a 5 kg block by a light st

Question

A 6 kg block rests on a horizontal table, attached to a 5 kg block by a light string as
shown in the figure.
The acceleration of gravity is 9.81 m/s2 .
What is the minimum coefficient of static
friction such that the objects remain at rest?

already got part 1: 0.833
need help on 2nd part

If the coefficient of static friction is less than
that found above, and if the coefficient of
kinetic friction between the block and the
table is 0.2, find the time it takes for the 5 kg
mass to fall 9 m to the floor if the system
starts from rest.
Answer in units of s

Explanation / Answer

m1g- T =m1a
T-m2g =m2a

So,g*(m1-m2) =(m1+m2)*a

So, a =3.3854 m/s^2

t= [2h/a]^0.5 =[2*9/3.3854]^0.5 =2.305 second

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