A student stands at the edge of a cliff and throws a stone horizontally over the

Question

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 17.0 m/s. The cliff is h = 24.0 m above a flat, horizontal beach as shown in the figure.

(a) What are the coordinates of the initial position of the stone?
x0 = m
y0 = m


(b) What are the components of the initial velocity?
v0x = m/s
v0y = m/s

(c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)
vx =
vy =

(d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)
x =
y =


(e) How long after being released does the stone strike the beach below the cliff?
s

(f) With what speed and angle of impact does the stone land?
vf = m/s
? = ° below the horizontal

Explanation / Answer

Considering origin at the base of the cliff, the answers are
a) x0=0
y0=24

b) v0x = 17
v0y = 0

c) vx = 17
vy = gt
where t is the time in seconds and g is the acceleration due to gravity.

d) x = 17t
y = (g/2)(t^2)

e) 2.2
here value of accleration due to gravity (g) considered is 9.8m/(s^2)
f) vf = 27.55
51.89 degrees below the horizontal

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