c. Not every cell in the body will respond to the epinephrine. Explain why not?
ID: 195971 • Letter: C
Question
c. Not every cell in the body will respond to the epinephrine. Explain why not? Part 2: Later in the night, the student takes another drug that renders hexokinases !, Il andIlI onstitutively active (i.e. hexokinase activity cannot be reduced). No other enzyme is affected. He continues to gorge on the chocolate which contains high concentrations of glucose. a. Explain the consequences of the persistent hexokinase activity b. What will happen to the majority of cells in his body? The concentration of ATP in each cell stops increasing after a short time even though glucose levels in the plasma are extremely high. Describe the intracellular feedback system which operates to ensure that this occurs. c.Explanation / Answer
A. The majority of cells will stock up on glucose while levels are high. Hexokinase transfers a phosphate from ATP to glucose, forming glucose-6-phosphate(G6P). The first step in glycolysis is the phosphorylation of glucose by hexokinase. This reaction is important for its ability to trap glucose within the cell. Whereas glucose can easily traverse the plasma membrane, the negatively charged phosphate group prevents G6P from crossing, so cells can stock up on glucose while levels are high.
B. The hexokinase reaction is highly regulated, G6P providing a sort of negative feedback inhibition of the enzyme hexokinase, as long as hexokinase is not present there is no need for converting ATP to ADP and further glycolysis stops. If further glycolysis stops there is no production of ATP
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.