<p>A swimmer wants to cross a river, from point A to point B, as shown in the fi

Question

<p>A swimmer wants to cross a river, from point A to point B, as shown in the figure. The distance d1 (from A to C) is 200m , the distance d2 (from C to B) is 150m , and the speed of the current in the river is 5km/hour . Suppose that the swimmer's velocity relative to the water makes an angle of theta=45degrees with the line from A to C, as indicated in the figure.<br /><br />a)To swim directly from A to B, what speed v(s) , relative to the water, should the swimmer have?</p>
<p>&#160;</p>
<p><img src="http://session.masteringphysics.com/problemAsset/1006765/13/M2K_rm_2_v1_001.jpg" alt="M2K_rm_2_v1_001.jpg" width="320" height="260" /></p>

Explanation / Answer

d1 =.200km d2 = .150km V(water) = 5km/hr Essentially, the river will carry the swimmer5km downstream per hour he is in the water. To solve, youmust keep in mind the y velocity and x velocities are separate. This means that you must find the time required to be in thewater for the swimmer to be carried that far downstream. d2/V(water) = .030 hours ...I'm keeping to3 sig digs. Then, divide d1 by the velocity of the water tofind the speed you want your swimmer to swim. .200/.03 = 6.67 km/hr

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