1. Suppose the space shuttle is in orbit 330 km from the Earth\'s surface, and c

Question

1. Suppose the space shuttle is in orbit 330 km from the Earth's surface, and circles the Earth about once every 91.1 minutes. Find the centripetal acceleration of the space shuttle in its orbit. Express your answer in terms of g, the gravitational acceleration at the Earth's surface.

2. Two objects attract each other gravitationally with a force of 3.3 10-10 N when they are 0.25 m apart. Their total mass is 4.0 kg. Find their individual masses.

larger mass () kg

smaller mass () kg

Explanation / Answer

Hello, centrip accel = v^2/r we need to find the speed and the radius the speed is the distance traveled/time the distance is the radius of the orbit, or 2 pi r; the time is the period P so v=2 pi r/P and v^2=4 pi^2 r^2/P^2 then a=v^2/r = 4 pi^2 r/P^2 r=radius of earth + 330 km = 6400 km + 330 km = 6730 km = 6.73x10^6m P=91.1 mins = 91.1 minsx60 sec/min = 5466s a=4 pi^2 (6.73x10^6)/(5466)^2 = 8.9 m/s/s => 8.5/9.8 = 0.91g

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