A 6.00-kg block is in contact with a 4.00-kg block on a horizontal frictionless

Question

A 6.00-kg block is in contact with a 4.00-kg block on a horizontal frictionless surface as shown in the figure. The 6.00-kg block is being pushed by a horizontal 20.0-N force as shown. What is the magnitude of the force that the 6.00-kg block exerts on the 4.00-kg block?

A. 6.00 N

B. 10.0 N

C. 20.0 N

D. 8.00 N

E. 4.00 N

A. 6.00 N

B. 10.0 N

C. 20.0 N

D. 8.00 N

E. 4.00 N

A 6.00-kg block is in contact with a 4.00-kg block on a horizontal frictionless surface as shown in the figure. The 6.00-kg block is being pushed by a horizontal 20.0-N force as shown. What is the magnitude of the force that the 6.00-kg block exerts on the 4.00-kg block? A. 6.00 N B. 10.0 N C. 20.0 N D. 8.00 N E. 4.00 N

Explanation / Answer

force = 4/ ( 4+6) * 20 = 4* 20 / 10 = 8 N

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