1)A 4.4 kg particle starts from rest and moves a distance of 5.8 m in 1.1 s unde

Question

1)A 4.4 kg particle starts from rest and moves a
distance of 5.8 m in 1.1 s under the action of
a single, constant force.
Find the magnitude of the force.
Answer in units of N

2) A 6.8 kg block initially at rest is pulled to the
right along a horizontal, frictionless surface
by a constant, horizontal force of 12.4 N.
Find the speed of the block after it has
moved 4.5 m.

3) A 59 kg boy and a 42 kg girl use an elastic rope
while engaged in a tug-of-war on a frictionless
icy surface.
If the acceleration of the girl toward the
boy is 2.2 m/s2
determine the magnitude of
the acceleration of the boy toward the girl.
Answer in units of m/s2

Explanation / Answer

1)distance traveled = 5.8 m time taken = 1.1 sec using equation of motion s= u*t + .5*a*t^2 5.8 = 0 + .5*a*1.1^2 a = 5.8/(.5*1.1*1.1) = 9.58677686 m/s^2 Force = m*a = 9.58677686*4.4 = 42.181N 2)acceleration of the block = 12.4/6.8 = 1.823529 m/s^2 distance traveled = 4.5 m using equation of motion v^2 = u^2 + 2*a*s v^2 = 2*1.823529*4.5 = 16.411 v = 4.05114317 3)Force with with both boy and girl experiences is the same since both are getting their forces from the tension in the wire. accelration of girl = 2.2 mass of girl = 42 kg Force on girl = 42*2.2 = 92.4 N This is the same force which acts on the boy so its acceleration is a = F/m = 92.4/59 = 1.5661 m/s^2

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