Researchers have created every possible \"knockout\" line in yeast. Each line ha

Question

Researchers have created every possible "knockout" line in yeast. Each line has exactly one gene deleted and all the other genes present (Steinmetz et al. 2002). The growth rate - how fast the number of cells increases per hour - of each of these yeast lines has also been measured, expressed as a multiple of the growth rate of the wild type that has all the genes present. In other words, a growth rate greater than 1 means that a given knockout line grows faster than the wild type, whereas a growth rate less than 1 means it grows more slowly. Below is the growth rate of a random sample of knockout lines:

0.6, 0.72, 1.03, 0.95, 0.99, 0.96, 0.72, 0.96, 0.93, 0.88, 0.92

What is the standard deviation of growth rate this sample of yeast lines (answer to 3 decimals)?

Explanation / Answer

The mean of the samples are = (0.6+0.72+1.03+0.95+0.99+0.96+0.72+0.96+0.93+0.88+0.92)/11= 0.878182

Standard deviation in growth rate x = sqrt(sum((x-)^2)/N) = 0.136368 = 0.136.

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