A fish swimming in a horizontal plane has velocity <img title=\"varrowbold\"

ID: 1962590 • Letter: #

Question

A fish swimming in a horizontal plane has velocity <img title="varrowbold" src="http://www.webassign.net/images/varrowbold.gif" alt="varrowbold" />i = (4.00 <img title="ihatbold" src="http://www.webassign.net/images/ihatbold.gif" alt="ihatbold" /> + 1.00 <img title="jhatbold" src="http://www.webassign.net/images/jhatbold.gif" alt="jhatbold" />) m/s at a point in the ocean where the position relative to a certain rock is <img title="rarrowbold" src="http://www.webassign.net/images/rarrowbold.gif" alt="rarrowbold" />i = (12.0 <img title="ihatbold" src="http://www.webassign.net/images/ihatbold.gif" alt="ihatbold" /> − 2.00 <img title="jhatbold" src="http://www.webassign.net/images/jhatbold.gif" alt="jhatbold" />) m. After the fish swims with constant acceleration for 19.0 s, its velocity is <img title="varrowbold" src="http://www.webassign.net/images/varrowbold.gif" alt="varrowbold" /> = (21.0 <img title="ihatbold" src="http://www.webassign.net/images/ihatbold.gif" alt="ihatbold" /> − 3.00 <img title="jhatbold" src="http://www.webassign.net/images/jhatbold.gif" alt="jhatbold" />) m/s. (a) What are the components of the acceleration of the fish?
<table>
<tbody>
<tr>
<td>ax =</td>
<td> 1<input id="RN_1742818_3_0_1746378" dir="ltr" name="RN_1742818_3_0_1746378" size="10" type="text" value="0.89" /> m/s2</td>
</tr>
</tbody>
</table>
<table>
<tbody>
<tr>
<td>ay =</td>
<td> 2<input id="RN_1742818_3_1_1746378" dir="ltr" name="RN_1742818_3_1_1746378" size="10" type="text" value="-0.210" />  m/s2</td>
</tr>
</tbody>
</table>
 (b) What is the direction of its acceleration with respect to unit vector <img title="ihatbold" src="http://www.webassign.net/images/ihatbold.gif" alt="ihatbold" />? 3<input id="RN_1742818_3_2_1746378" dir="ltr" name="RN_1742818_3_2_1746378" size="10" type="text" value="346.72" />  ° counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 26.0 s?
<table>
<tbody>
<tr>
<td>x =</td>
<td> 4<input id="RN_1742818_3_3_1746378" dir="ltr" name="RN_1742818_3_3_1746378" size="10" type="text" value="416.82" />  m</td>
</tr>
</tbody>
</table>
<table>
<tbody>
<tr>
<td>y =</td>
<td> 5<input id="RN_1742818_3_4_1746378" dir="ltr" name="RN_1742818_3_4_1746378" size="10" type="text" value="-46.98" />  m</td>
</tr>
</tbody>
</table>
 In what direction is it moving? 6<input id="RN_1742818_3_5_1746378" dir="ltr" name="RN_1742818_3_5_1746378" size="10" type="text" value="-352.21" /> ° counterclockwise from the +x-axis
 
I got all but the direction,can any1 help me with it

Explanation / Answer

Hello, I couldn't recognize your question very well, but I assumed the variables, and the solution is as follows: (a) a = (v-vi)/t = [(20.0 i - 5.00 j) - (4.00 i + 1.00 j)]/23 = [16i - 6j]/23 ax = 16.0/23.0 m/s2 ay = -6.0/23.0 m/s2 (b) tan^-1(-6/16) = -20.56° -20.56° + 360° = 339.44° (c) r = ri + (vi)t + (1/2)at^2 = (10.0 i - 4.00 j) + 25(4.00 i + 1.00 j) + (25.0^2)(1/2)[16.0i - 6.0j]/23 = (10.0 i - 4.00 j) + (100.00 i + 25.00 j) + (625)[8.0i - 3.0j]/23 = (110.00 i + 21.00 j) + [217i - 81.5j] = (327i - 60.5j) m x = 327 m y = -60.5 m v = vi + at = (4.00 i + 1.00 j) + 25[16i - 6j]/23 = (21.4i - 5.5j) m/s tan^-1(-5.5/21.4) = -14.5° -14.5° + 360° = 345.5°

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<p>A fish swimming in a horizontal plane has velocity <img title=\"varrowbold\"

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