In a physics lab experiment, a 7.00 kg box is pushed across a flat table by a ho

Question

In a physics lab experiment, a 7.00 kg box is pushed across a flat table by a horizontal force F.

* If the box is moving at a constant speed of 0.340 and the coefficient of kinetic friction is 0.120, what is the magnitude of F?

* What is the magnitude of F if the box is speeding up with a constant acceleration of 0.200 m/s^2 ?

* How would your answer to part (A) change if the experiments were performed on the moon, where Gm = 1.62 m/s^2?

* How would your answer to part (B) change if the experiments were performed on the moon, where Gm = 1.62 m/s^2?

Explanation / Answer

Mass of box = 7 kg
(i) As the box is moving at a constant speed the acceleration= 0
So Force F = mg = 0.12 * 7 * 9.8 = 8.232 N

(ii) Acceleration of box = 0.2 m/s^2

So in the present of friction F = mg + ma = (0.12 * 7 * 9.8) + (7 * 0.2) = 9.632 N

If there is no friction F = ma = 7 * 0.2 = 1.4 N

(iii)

Here force F = mg = 0.12 * 7 * 1.62 = 1.361 N

(iv)

Now in present of friction force F = mg + ma = (0.12 * 7 *1.62) + (7 * 0.2) = 2.761 N

If there is no friction F = ma = 7 * 0.2 = 1.4 N

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