This is the first time doing this, so please bear with me, lol. This is a pretty

Question

This is the first time doing this, so please bear with me, lol. This is a pretty simple problem, but if possible, I would like as detailed an answer as possible because I would like to use this as a model for other similar problems. Thank you.

A 65Kg diver stands at the end of a 28Kg springboard, as shown in the figure. The board is attached to a hinge at the left end but simply rests on the right support.

      1.5m
I----------------I

_____________________X

^                   ^

I-------------------------------I
                 3m

What is the magnitude of the vertical force exerted by the hinge on the board?

I hope the picture was clear. I made it the best I could. The X is the person, and the two ^ are the supports.

Explanation / Answer

Let the supports be 1 and 2. and the forces on both be F1 and F2 standing at the centre and balancing torque, we get F1* 1.5= 65g *1.5 F1=65g=637N downwards and standing at the end with the person, F1 *3= F2*1.5 F2= 2*65*9.8=1274 N but this 130g is the net force which includes the 28g force downwards due to the weight of the plank....hence the force in the up direction would be 158g (1548.4N upwards)

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