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At a certain location in the Southern Hemisphere, Earth\'s magnetic field has a

ID: 1964137 • Letter: A

Question

At a certain location in the Southern Hemisphere, Earth's magnetic field has a magnitude of 42.0 T and points upward at an angle = 66° to the vertical. Calculate the flux through a horizontal surface of area 2.50 m2 as shown in the figure. The area vector A has arbitrarily been chosen to be upward. The flux is in webers = Wb.

(please show work! thanks!)

At a certain location in the Southern Hemisphere, Earth's magnetic field has a magnitude of 42.0 MuT and points upward at an angle theta = 66 degree to the vertical. Calculate the flux through a horizontal surface of area 2.50 m2 as shown in the figure. The area vector A has arbitrarily been chosen to be upward. The flux is in webers = Wb. (please show work! thanks!)

Explanation / Answer

flux= = dot product of B and A vectors
component of earth's magnetic field along vertical direction = Bcos
flux = Bcos x A
= 42 x 10-6 x cos(66) x 2.5
= 42.71 x 10-6 Wb

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