Two masses are connected by a string which passes over a frictionless, mass less
ID: 1964935 • Letter: T
Question
Two masses are connected by a string which passes over a frictionless, mass less pulley. One mass hangs vertically and one mass slides on a 30 degrees incline. The vertically hanging mass is 6.0 kg and the mass on the incline is 4.0 kg. The acceleration of the 4.0 kg mass is,
The answer is 3.92 m/s.
When setting up components for the mass on the incline this is what I got...
x:mgsin +T = ma
y: -T+ mg = ma
I understand that the positive forces will be in the same direction as acceleration...but then why would the correct x component be:
x: -mgsin + T=ma
I thought there was NO friction.
Explanation / Answer
If we consider the direction of acceleration of the block to up the incline,
then we while writing the equation of motion , we write the forces which are in same direction as acceleration to be positive and the one in opposite direction to be negative,
Here tension T is in same direction, whereas mgsin acts down the slope, and is negative
hence, we have
ma = T - mgsin
Cheers !!
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