In a football game a kicker attempts a field goal. The ball remains in contact w

Question

In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.050 seconds, during which time it experiences an acceleration of 340 m/s^2. The ball is launched at an angle of 51 degrees above the ground. Determine the horizontal and vertical components of the launch velocity.
ax=340(cos51) =237.97 m/s^2
ay=340(sin51) =264.23m/s^2
vx=237.97*.050s=11.90 m/s
vy=264.23*0.050s= 13.2 m/s
If the football was placed 30m (32.8 yards) away from the goal
a.) How long does the ball take to get to the goal?
b.) how high would the ball be when it passes the goal?

Explanation / Answer

<p>The x component and y components are completely independent.<br /> a) If it is 30 m away, you only need the x component. 30/(sin51*340*.050)=2.8 seconds</p><br /> b) You can use the kinematic equation delta y=initial velocity * time + 1.2*acceleration+time^2<br /> you use the time you found in part a) and the velocities are with respects to the vertical<br /> delta y=(sin51*340*.05)(2.8)-(1/2)(9.81)(2.8^2)=-1.46 m<br /> Actually, i dont think the ball reaches the goal 0.o</p></p> I dont know why all this html code is showing up...

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