In Figure 9-43, two particles are launched from the origin of the coordinate sys

Question

In Figure 9-43, two particles are launched from the origin of the coordinate system at time t = 0. Particle 1 of mass m1 = 6.60 g is shot directly along the x axis (on a frictionless floor), where it moves with a constant speed of 12.3 m/s. Particle 2 of mass m2 = 2.20 g is shot with a velocity of magnitude 19.7 m/s, at an upward angle such that it always stays directly above particle 1 during its flight. (a) What is the maximum height Hmax reached by the com of the two-particle system? In unit-vector notation, what are the (b) velocity and (c) acceleration of the com when the com reaches Hmax?

Explanation / Answer

a) max height reached by particle 2 = 19.7^2-12.3^2/2*9.8 = 12.081m max height reached by COM = (6.6*0 + 2.2*12.08)/(6.6+2.2) = 3.02 m b) velocity in y direction =0 velocity in x direction = (6.6*12.3 + 2.2*12.3)/(6.6+2.2) = 12.3 m/s velocity = 12.3 m/s in x direction c) acceleration in x direction =o in y direction it is (6.6*0 - 2.2*9.8)/(6.6+2.2) = -2.45 m/s^2 acceleration of COM = -2.45 m/s^2 in negative y direction

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.