Suppose that the resistor arrangement in the figure is connected to a 12V batter

Question

Suppose that the resistor arrangement in the figure is connected to a 12V battery.
Part A
What will be the current in each resistor?
Express your answers using two significant figures separated by commas.


Suppose that the resistor arrangement in the figure is connected to a 12V battery.
Part A
What will be the current in each resistor?
Express your answers using two significant figures separated by commas.

Part B
What will be the voltage drop across each resistor?
Express your answers using two significant figures separated by commas.

Part C
What will be the total power delivered?

Please help! stuck on this Hw problem!

Explanation / Answer

resistance R1 and R2 are connected in series Ra=R1+R2=2+2=4ohm Ra,R2,R3 are connected in parallel total resistance=R 1/R=1/Ra +1/R3+1/R4 =1/4 +1/2 +1/2 R=4/5=0.8ohm Total current=Voltage/R =12/0.8 =15A current through R3=V/R3=12/2=6.00A current through R4=12/2=6.00A current through Ra=15-6-6=3.00A current through R1=3.00A current through R2=3.00A Voltage across R1=3*2=6.00V Voltage across R2=3*2=6.00V [V=iR] Voltage across R3=6*2=12.00V Voltage across R4=6*2=12.00V power dissipated in R1=i^2R=3^2*2=18.00W power dissipated in R2=i^2R=3^2*2=18.00W power dissipated in R3=i^2R=6^2*2=72.00W power dissipated in R4=i^2R=6^2*2=72.00W

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