In this problem, use g = 10.0 m/s 2 . A rubber ball, with a mass of 50.0 grams i

Question

In this problem, use g = 10.0 m/s2.
A rubber ball, with a mass of 50.0 grams is dropped from rest from a height of 1.50 m above the floor. It hits the floor, and then reaches a maximum height of 70.0 cm when it comes back up again.

(a) The collision with the floor causes some mechanical energy to be lost (this energy generally ends up as thermal energy). How much mechanical energy is lost in this case?
1_____________ J

(b) What is the ball's speed, just as it leaves the floor on its way up?
_____________m/s

(c) What is the magnitude of the impulse experienced by the ball for the entire time it is in contact with the floor?
_____________kg m/s

Explanation / Answer

a)mechanical energy lost= Difference in PE = mg( 1.50 - 0.70)= 0.4 J mechanincal energy lost = 0.4 J b) u^2 = 2gh u =sqrt(2gh) = sqrt( 2 x10 x 0.70)= 3.74 m/s c)velocity with which ball hits the ground mgh = 0.5mv^2 gh=0.5v^2 10x 1.50 x 2 = v^2 v=5.477 m/s impulse = change in mommentum = m(V1-V2) =50*10^-3*(5.477-(-3.74)) =0.461Kgm/s

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