(a) What is the ship\'s kinetic energy at this time? 2.989E16 Incorrect: Your an

Question

(a) What is the ship's kinetic energy at this time?
2.989E16 Incorrect: Your answer is incorrect.
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J
^ I've done this problem:
(1/2)(12.2)((7.00*10^7)^2)=2.989e16 and it says it's wrong (is it, that webassign isn't reading it right?)

(b) How much work is required to stop it? (Include the sign of this value.)
(-2.989e16 J)? right?

(c) What is the magnitude of the constant force required to stop it as it undergoes a displacement of 2.00 km?
N
(not sure how to go about this)

Since the first answer seems to be wrong ... how do I proceed into the next?

Explanation / Answer

a) KE = 05mv^2 = 0.5( 7 x 107) ( 12.2)2= 520.94 x 107 J

b) work don e= chnage in kE = Final KE - iNitial KE = 0 - 520.94 x 107 = - 520.94 x 107 J

c) work don e= forc ex displacemnent

520.94 x 107= F ( 2000m)

F = 260.47 x 104 N apprx----------force applied

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