I have a question in regards to work and kinetic energy. The question is #2 in C
ID: 1971443 • Letter: I
Question
I have a question in regards to work and kinetic energy. The question is #2 in Chapter 7 of Physics for Scientists and Engineers 6th Edition by Mosca and Tipler. The actual question reads: You push a heavy box in a straight line along the top of a rough horizontal table. The box starts at rest and ends at rest. Describe the work done on it (including sign-meaning positive(+) and negative(-)) by each force acting on it and the net work done on it. Including a drawing would be very helpful too. I would really appreciate the help.Explanation / Answer
work is done by both the friction and man since the block is moving in direction of force of man the work done by man is positive w=f*d as the friction resists the motion it will act in opposite direction of movement and hence the work done by it will be negative. now we have total work done=change in kinetic energy as the block is at rest in both in its initial and final position its kinetic energy will be zero at both position so no change therefore the net work done will be zero so work done by friction=work done by man..
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